The Pi Day Taxicab Puzzle
On March 14, Grant Sanderson tweeted: “Happy Pi Day! In a certain sense, π is not a constant, but a variable... applying other L^p norms on ℝ², half the unit circle's perimeter will give other values. For instance, at p=1 (taxicab geometry), “π” = 2√2.”
Shortly after, he followed up: “Ah! Correction, as many have pointed out, it should be 4 in the taxicab metric.”
Why the discrepancy? The unit circle for p=1 is the square diamond connecting (1,0), (0,1), (-1,0), and (0,-1). Each edge has Euclidean length √(1² + 1²) = √2. Four edges equal 4√2, so half-perimeter is 2√2 ≈ 2.8284.
Measuring With the Metric Itself
When geometry is defined by the taxicab norm ‖(x,y)‖₁ = |x| + |y|, distance is not measured by diagonal Euclidean rulers. Stepping along a segment from (1,0) to (0,1) incurs |Δx| + |Δy| = 1 + 1 = 2 units of distance!
Thus, each of the four sides of the diamond has intrinsic length 2, giving a total perimeter of 8. Therefore, the intrinsic half-perimeter is exactly 8 / 2 = 4!
In general Minkowski spaces (normed linear spaces), the Busemann and Schäffer definitions of metric circumference show that for any symmetric convex unit ball in ℝ², the intrinsic perimeter is always between 6 and 8, meaning intrinsic “π” lies in [3, 4].