Starship & LEO Multi-Orbit Profile

Orbital Mission & Ground Track Planner

Simulate orbital trajectories, Earth rotation ground tracks, eclipse daylight/shadow windows, and ground station telemetry passes over hours of sustained spaceflight.

TARGET: STARSHIP S36 / FT-14 | ALT: 210.4 km | VEL: 7.79 km/s
STATUS: SUNLIGHT (ORBIT 1) | LAT/LON: 26.0° N, 97.2° W
Past Ground Track
Future Ground Track
Current Spacecraft Position
Day / Night Terminator
Ground Station LOS Radius
Orbit # Ground Station Acquisition (AOS) Loss of Signal (LOS) Duration Max Elevation
Orbit computed: 6.77 revolutions over 10.0 hours.

The Physics of Multi-Orbit Endurance Tests

For Starship’s Flight 14, remaining in orbit for 10 hours represents a massive operational leap beyond early suborbital test trajectories. A standard Low Earth Orbit (LEO) at ~200 km altitude takes approximately 88.5 minutes to complete one full revolution.

Over a 10-hour flight, the spacecraft executes roughly 6.8 complete orbits. Because the Earth rotates eastward beneath the inclined orbital plane at 15.04° per hour (plus nodal precession caused by the Earth’s oblateness J₂), each successive equator crossing shifts westward by ~22.5° longitude. This ground-track shift exposes the ship to differing telemetry tracking stations and dynamic thermal sun/shadow cycles.

Mission Critical Checkpoints in a 10-Hour Orbit

  • Thermal Soaking & Boil-off: Continuous alternating 54-minute sunlight / 35-minute shadow periods test vacuum cryogenic propellant insulation.
  • Ground Telemetry Handoffs: Tracking relays switch between Starbase (TX), Bermuda, Hawaii, Guam, and maritime tracking vessels.
  • Microgravity RCS & Relight: Settling propellants and executing in-space Raptor vacuum engine relight tests.
  • Deorbit Burn Timing: A ~95–110 m/s retrograde burn lowers perigee into the atmosphere for targeted reentry over the Indian or Pacific Ocean.
How does the simulator calculate ground tracks and J₂ nodal regression?

The orbital period is derived from Kepler's third law: T = 2π √(a³ / μ) where μ = 398600.4418 km³/s² and a = R_earth + (r_perigee + r_apogee)/2. As the satellite progresses along its true anomaly, Earth rotates at ωearth = 7.292115 × 10⁻⁵ rad/s. Furthermore, the oblateness of the Earth (J₂ perturbation = 1.08263 × 10⁻³) causes a secular regression of the ascending node ΔΩJ2 ≈ -9.9639 × (R_E / a)3.5 × cos(i) deg/day, shifting the ground track on every subsequent orbit.

What is required for a safe deorbit burn?

To safely deorbit from a 200 km circular orbit into an atmospheric entry interface (nominally ~80–100 km), the spacecraft fires its engines opposite the velocity vector (retrograde). A delta-V (ΔV) of ~85 to 110 m/s reduces perigee below 50 km, ensuring atmospheric drag will capture the vehicle on the planned ocean corridor.

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