Transfer check. Double the line distance while every electrical assumption stays fixed.
The selected voltage is the lowest of 33, 220, 400 and 765 kV that satisfies this simplified resistive-loss ceiling. It is not a complete engineering design decision.
The tool holds three phase power fixed and computes current as power divided by square root of three, line voltage, and power factor. The default power is one hundred megawatts and power factor zero point nine five. At two hundred twenty kilovolts, current is about two hundred seventy six point two amperes. Doubling voltage would halve current when power and power factor stay fixed. This is the model equation, not a live grid measurement. The entered distance is three hundred kilometers and resistance per kilometer is zero point zero three ohms. The model multiplies them to get nine ohms per phase. Three phase line loss is three times current squared times that resistance. At two hundred seventy six point two amperes the loss is about two point zero six one megawatts, or two point zero six one percent of the entered one hundred megawatts. Halving current quarters the resistive loss. The tool lists thirty three, two hundred twenty, four hundred, and seven hundred sixty five kilovolt stages. It chooses the first whose loss percentage is below the entered ceiling. At the default three percent ceiling, two hundred twenty kilovolts passes. Doubling distance to six hundred kilometers doubles phase resistance and doubles loss at unchanged current. The two hundred twenty kilovolt result becomes about four point one two two percent and fails; four hundred kilovolts becomes the first passing listed stage. This ideal resistive comparison excludes reactive flow, limits and actual network operations.